The function foo2 will be called iff the condition if(C<D) evaluates to be true.
Given that C<D turns out to be true 75% times.So why the call to foo2
will be independent??
I think it is only the simple math.Correct me if I am wrong..
On 12/15/10, ankit sablok <ankit4...@gmail.com> wrote:
> what i think is that the number of times foo2 being called is
> independent of the percentages given in the question it may be called
> 5000 times or 4999 times and continuinf in this fashion also none of
> the times as in every case there's 1/4 probability of A<B and 3/4 of
> C<D so as per me we cannot decide givn the percentage of success and
> failure any suggestions are always welcomed
>
> On Dec 15, 12:06 am, bittu <shashank7andr...@gmail.com> wrote:
>> void foo1()
>> {
>> if(A<B)
>> Then {_/*.... */}
>> else
>> if(C<D)
>> then foo2()
>>
>> }
>>
>> How many time foo2() would get called given
>> A<B 25% of the times and C<D 75% of the times and foo1() is called
>> 5000 times
>>
>> although i had diff...solution..but i wants to confirm wid others..so
>> hav a look
>>
>> Regards
>> Shashank Mani
>> BIT Mesra
>
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