well i still believe that the calling of foo2 is independent plzzz suggest
me the solution if i am wrong a detailed one thanx in advance
On Wed, Dec 15, 2010 at 1:22 AM, Saurabh Koar <saurabhkoar...@gmail.com>wrote:
> The function foo2 will be called iff the condition if(C<D) evaluates to be
> true.
> Given that C<D turns out to be true 75% times.So why the call to foo2
> will be independent??
> I think it is only the simple math.Correct me if I am wrong..
>
> On 12/15/10, ankit sablok <ankit4...@gmail.com> wrote:
> > what i think is that the number of times foo2 being called is
> > independent of the percentages given in the question it may be called
> > 5000 times or 4999 times and continuinf in this fashion also none of
> > the times as in every case there's 1/4 probability of A<B and 3/4 of
> > C<D so as per me we cannot decide givn the percentage of success and
> > failure any suggestions are always welcomed
> >
> > On Dec 15, 12:06 am, bittu <shashank7andr...@gmail.com> wrote:
> >> void foo1()
> >> {
> >> if(A<B)
> >> Then {_/*.... */}
> >> else
> >> if(C<D)
> >> then foo2()
> >>
> >> }
> >>
> >> How many time foo2() would get called given
> >> A<B 25% of the times and C<D 75% of the times and foo1() is called
> >> 5000 times
> >>
> >> although i had diff...solution..but i wants to confirm wid others..so
> >> hav a look
> >>
> >> Regards
> >> Shashank Mani
> >> BIT Mesra
> >
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