Will this work ?

Find the node x, then the node y within the sub tree rooted at x and then z
within the sub tree rooted at y since they must within a unique path
If any of those searches fails there are no such nodes

On Sun, Jan 9, 2011 at 6:02 AM, Gene <gene.ress...@gmail.com> wrote:

> The problem never says that the tree is rooted. So LCA is not
> very relevant.
>
> The path between two nodes in any tree is unique. (Otherwise it has a cycle
> and is not a tree.)  So all that's needed is to search for z starting at x
> (DFS or BFS will work fine).  When you find the unique path, see if it
> contains y.  This is O(n) where n is the number of nodes.
>
> The problem is more interesting if you are allowed to pre-process the tree
> one time in order to build a data structure to support many queries.
>
>
>
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