so if its in another subtree, whats the problem? If z is not reachable print 'no'.
On Sun, Jan 9, 2011 at 5:32 PM, juver++ <avpostni...@gmail.com> wrote: > Your approach is failed! Read my previous post. > There is a simple counterexample when doing dfs from x we cannot reach > target node cause z can be placeed into another subtree, so > x is not its ancestor. > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- S.Nishaanth, Computer Science and engineering, IIT Madras. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
