I think c) $300
On Wed, Jan 12, 2011 at 3:17 PM, snehal jain <learner....@gmail.com> wrote:
> An insurance company issues a policy on a small boat under the following
> conditions:
> The replacement cost of $5000 will be paid for a total loss. If it is not a
> total loss,
> but the damage is more than $2000, then $1500 will be paid. Nothing will be
> paid for damage costing $2000 or less and of course nothing is paid out if
> there
> is no damage. The company estimates the probability of the first three
> events
> as .02, .10, and .30 respectively. The amount the company should charge for
> the
> policy if it wishes to make a profit of $50 per policy on average is:
> a) $250
> b) $201
> c) $300
> d) $1200
>
>
> On Wed, Jan 12, 2011 at 3:15 PM, snehal jain <learner....@gmail.com>wrote:
>
>> A 4-stage pipeline has the stage delays as 150, 120, 160 and 140 ns
>> (nano seconds)
>> respectively. Registers that are used between the stages have a delay
>> of 5 ns each. Assuming
>> constant clocking rate, the total time taken to process 1000 data
>> items on this pipeline will
>> approximately be
>> a. 120 us (micro seconds)
>> b. 165 us
>> c. 180 us
>> d. 175 us
>>
>> Which of the following statements are true?
>> I Shortest remaining time first scheduling may cause starvation
>> II Preemptive scheduling may cause starvation
>> III Round robin is better than first come first serve in terms of
>> response time
>> a) I only
>> b) I and III only
>> c) II and III only
>> d) I, II and III
>>
>> Increasing the RAM of a computer typically improves performance
>> because:
>> a. Virtual memory increases
>> b. Larger RAMs are faster
>> c. Fewer segmentation faults occur
>> d. Fewer page faults occur
>>
>> Suppose we want to synchronize two concurrent processes P and Q using
>> binary
>> semaphores S and T. The code for the processes P and Q is shown below.
>> Process P:
>> while (1) {
>> W:
>> print '0’;
>> print '0';
>> X:
>> }
>> Process Q:
>> while (1) {
>> Y:
>> print '1'
>> print '1'
>> Z:
>> }
>> Synchronization statements can be inserted only at points W, X, Y and
>> Z.
>> V() increments the semaphore, whereas P() decrements it
>> Which of the following will always lead to an output staring with
>> '001100110011' ?
>> a) P(S) at W, V(S) at X, P(T) at Y, V(T) at Z, S and T initially 1
>> b) P(S) at W, V(T) at X, P(T) at Y, V(S) at Z, S initially 1, and T
>> initially 0
>> c) P(S) at W, V(T) at X, P(T) at Y, V(S) at Z, S and T initially 1
>> d) P(S) at W, V(S) at X, p(T) at Y, V(T) at Z, S initially 1, and T
>> initially 0
>>
>>
>> can any1 suggest some source for such kind of questions????????
>>
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Cheers
Naveen Kumar
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