int a=10,b;
b=a++ + ++a; (Till here I think it is clear the value of a is 12 and b = 22)
printf("%d,%d,%d,%d",b,a++,a,++a); (Evaluate from right to left. So ++a
makes the value of a as 13, then a and then a++ which is post increment
still makes a as 13)
Now it try to display the value from left to right which makes a++ as 13,
then a has 14 and ++a as 14
I hope it is clear.
On Sun, Feb 6, 2011 at 8:40 PM, jagannath prasad das <jpdasi...@gmail.com>wrote:
> ya i also want the explaination of gcc compiler output.......thanx in
> advance
>
> On Sun, Feb 6, 2011 at 10:13 AM, tech rascal <techrascal...@gmail.com>wrote:
>
>> but can nybody explain why the output is coming like this on gcc
>> compiler??
>> On Sun, Feb 6, 2011 at 10:04 AM, Manish Verma <monsieur....@gmail.com>wrote:
>>
>>>
>>> i think juver has explained
>>> On Feb 5, 9:34 pm, jagannath prasad das <jpdasi...@gmail.com> wrote:
>>> > @manish:can you explain with the example of a specific compiler...
>>> >
>>> > On Sat, Feb 5, 2011 at 10:02 PM, jagannath prasad das
>>> > <jpdasi...@gmail.com>wrote:
>>> >
>>> >
>>> >
>>> > > @ankit:ans is 22 13 14 14 in gcc compiler.............
>>> >
>>> > > On Sat, Feb 5, 2011 at 7:24 PM, Manish Verma <monsieur....@gmail.com
>>> >wrote:
>>> >
>>> > >> answer will depend on your compiler.....
>>> >
>>> > >> On Feb 5, 1:02 am, jagannath prasad das <jpdasi...@gmail.com>
>>> wrote:
>>> > >> > *#include<stdio.h>
>>> > >> > void main(void)
>>> > >> > {
>>> > >> > int a=10,b;
>>> > >> > b=a++ + ++a;
>>> > >> > printf("%d,%d,%d,%d",b,a++,a,++a);
>>> >
>>> > >> > }
>>> >
>>> > >> > *what is the answer?how are the function parameters passed on the
>>> stack?
>>> >
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