@ anand: I didn't understand in printf, u r evaluating the values frm right to left n thn while printing, u hv to print the evaluated values, y u r again evaluating the values while u r printing frm left to right??
as in, u said- "Now it try to display the value from left to right which makes a++ as 13, then a has 14 and ++a as 14" so it has to be....acc. to u....a++ as 13, thn a as 14 and thn ++a shd b 15 thn. On Mon, Feb 7, 2011 at 11:01 AM, jagannath prasad das <jpdasi...@gmail.com>wrote: > @juver:in f(a)+f(b) i guess f(a) is evaluated first because fucntion calls > are evaluated from left to right > > > On Mon, Feb 7, 2011 at 10:37 AM, Anand <anandut2...@gmail.com> wrote: > >> a++ when it gets printed. it is 13 and now it gets increment to 14. So now >> if you print a it will 14. >> >> >> On Sun, Feb 6, 2011 at 9:04 PM, jagannath prasad das <jpdasi...@gmail.com >> > wrote: >> >>> @anand:while printing post fix gave 13 but rest two why 14 >>> >>> On Mon, Feb 7, 2011 at 10:28 AM, Anand <anandut2...@gmail.com> wrote: >>> >>>> int a=10,b; >>>> b=a++ + ++a; (Till here I think it is clear the value of a is 12 and b = >>>> 22) >>>> printf("%d,%d,%d,%d",b,a++,a,++a); (Evaluate from right to left. So >>>> ++a makes the value of a as 13, then a and then a++ which is post >>>> increment >>>> still makes a as 13) >>>> Now it try to display the value from left to right which makes a++ as >>>> 13, then a has 14 and ++a as 14 >>>> >>>> I hope it is clear. >>>> >>>> >>>> On Sun, Feb 6, 2011 at 8:40 PM, jagannath prasad das < >>>> jpdasi...@gmail.com> wrote: >>>> >>>>> ya i also want the explaination of gcc compiler output.......thanx in >>>>> advance >>>>> >>>>> On Sun, Feb 6, 2011 at 10:13 AM, tech rascal >>>>> <techrascal...@gmail.com>wrote: >>>>> >>>>>> but can nybody explain why the output is coming like this on gcc >>>>>> compiler?? >>>>>> On Sun, Feb 6, 2011 at 10:04 AM, Manish Verma <monsieur....@gmail.com >>>>>> > wrote: >>>>>> >>>>>>> >>>>>>> i think juver has explained >>>>>>> On Feb 5, 9:34 pm, jagannath prasad das <jpdasi...@gmail.com> wrote: >>>>>>> > @manish:can you explain with the example of a specific compiler... >>>>>>> > >>>>>>> > On Sat, Feb 5, 2011 at 10:02 PM, jagannath prasad das >>>>>>> > <jpdasi...@gmail.com>wrote: >>>>>>> > >>>>>>> > >>>>>>> > >>>>>>> > > @ankit:ans is 22 13 14 14 in gcc compiler............. >>>>>>> > >>>>>>> > > On Sat, Feb 5, 2011 at 7:24 PM, Manish Verma < >>>>>>> monsieur....@gmail.com>wrote: >>>>>>> > >>>>>>> > >> answer will depend on your compiler..... >>>>>>> > >>>>>>> > >> On Feb 5, 1:02 am, jagannath prasad das <jpdasi...@gmail.com> >>>>>>> wrote: >>>>>>> > >> > *#include<stdio.h> >>>>>>> > >> > void main(void) >>>>>>> > >> > { >>>>>>> > >> > int a=10,b; >>>>>>> > >> > b=a++ + ++a; >>>>>>> > >> > printf("%d,%d,%d,%d",b,a++,a,++a); >>>>>>> > >>>>>>> > >> > } >>>>>>> > >>>>>>> > >> > *what is the answer?how are the function parameters passed on >>>>>>> the stack? 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