@ anand: I didn't understand
in printf, u r evaluating the values frm right to left n thn while printing,
u hv to print the evaluated values, y u r again evaluating the values while
u r printing frm left to right??
as in, u said-
"Now it try to display the value from left to right which makes a++ as 13,
then a has 14 and ++a as 14"
so it has to be....acc. to u....a++ as 13, thn a as 14 and thn ++a shd b 15
thn.
On Mon, Feb 7, 2011 at 11:01 AM, jagannath prasad das
<jpdasi...@gmail.com>wrote:
> @juver:in f(a)+f(b) i guess f(a) is evaluated first because fucntion calls
> are evaluated from left to right
>
>
> On Mon, Feb 7, 2011 at 10:37 AM, Anand <anandut2...@gmail.com> wrote:
>
>> a++ when it gets printed. it is 13 and now it gets increment to 14. So now
>> if you print a it will 14.
>>
>>
>> On Sun, Feb 6, 2011 at 9:04 PM, jagannath prasad das <jpdasi...@gmail.com
>> > wrote:
>>
>>> @anand:while printing post fix gave 13 but rest two why 14
>>>
>>> On Mon, Feb 7, 2011 at 10:28 AM, Anand <anandut2...@gmail.com> wrote:
>>>
>>>> int a=10,b;
>>>> b=a++ + ++a; (Till here I think it is clear the value of a is 12 and b =
>>>> 22)
>>>> printf("%d,%d,%d,%d",b,a++,a,++a); (Evaluate from right to left. So
>>>> ++a makes the value of a as 13, then a and then a++ which is post
>>>> increment
>>>> still makes a as 13)
>>>> Now it try to display the value from left to right which makes a++ as
>>>> 13, then a has 14 and ++a as 14
>>>>
>>>> I hope it is clear.
>>>>
>>>>
>>>> On Sun, Feb 6, 2011 at 8:40 PM, jagannath prasad das <
>>>> jpdasi...@gmail.com> wrote:
>>>>
>>>>> ya i also want the explaination of gcc compiler output.......thanx in
>>>>> advance
>>>>>
>>>>> On Sun, Feb 6, 2011 at 10:13 AM, tech rascal
>>>>> <techrascal...@gmail.com>wrote:
>>>>>
>>>>>> but can nybody explain why the output is coming like this on gcc
>>>>>> compiler??
>>>>>> On Sun, Feb 6, 2011 at 10:04 AM, Manish Verma <monsieur....@gmail.com
>>>>>> > wrote:
>>>>>>
>>>>>>>
>>>>>>> i think juver has explained
>>>>>>> On Feb 5, 9:34 pm, jagannath prasad das <jpdasi...@gmail.com> wrote:
>>>>>>> > @manish:can you explain with the example of a specific compiler...
>>>>>>> >
>>>>>>> > On Sat, Feb 5, 2011 at 10:02 PM, jagannath prasad das
>>>>>>> > <jpdasi...@gmail.com>wrote:
>>>>>>> >
>>>>>>> >
>>>>>>> >
>>>>>>> > > @ankit:ans is 22 13 14 14 in gcc compiler.............
>>>>>>> >
>>>>>>> > > On Sat, Feb 5, 2011 at 7:24 PM, Manish Verma <
>>>>>>> monsieur....@gmail.com>wrote:
>>>>>>> >
>>>>>>> > >> answer will depend on your compiler.....
>>>>>>> >
>>>>>>> > >> On Feb 5, 1:02 am, jagannath prasad das <jpdasi...@gmail.com>
>>>>>>> wrote:
>>>>>>> > >> > *#include<stdio.h>
>>>>>>> > >> > void main(void)
>>>>>>> > >> > {
>>>>>>> > >> > int a=10,b;
>>>>>>> > >> > b=a++ + ++a;
>>>>>>> > >> > printf("%d,%d,%d,%d",b,a++,a,++a);
>>>>>>> >
>>>>>>> > >> > }
>>>>>>> >
>>>>>>> > >> > *what is the answer?how are the function parameters passed on
>>>>>>> the stack?
>>>>>>> >
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