Nothing... 10 in base 5 = 5 in base 10.
void change(){
printf(""); //...?
}
2011/2/15 Don <dondod...@gmail.com>
> A semicolon is valid in the middle of a line in C or C++.
>
> For instance, no one says that
>
> for(i = 0; i < 10; ++i)
>
> is three lines of code.
>
> Don
>
> On Feb 15, 11:31 am, jalaj jaiswal <jalaj.jaiswa...@gmail.com> wrote:
> > after termination of semicolon , that will be considered a separate line
> i
> > guess
> >
> >
> >
> > On Tue, Feb 15, 2011 at 10:59 PM, Don <dondod...@gmail.com> wrote:
> > > void change()
> > > {
> > > printf("10"); while(1) {}
> > > }
> >
> > > On Feb 15, 10:17 am, Balaji S <balaji.ceg...@gmail.com> wrote:
> > > > Insert only one line in the function change() so that the output of
> the
> > > > program is 10.
> > > > You are not allowed to use exit(). You are not allowed to edit the
> > > function
> > > > main() or to
> > > > pass the parameter to change()
> >
> > > > void change()
> > > > {
> > > > // Code here}
> >
> > > > int main()
> > > > {
> > > > int i=5;
> > > > change();
> > > > printf(“%d” ,i);
> > > > return 0;
> >
> > > > }
> >
> > > --
> > > You received this message because you are subscribed to the Google
> Groups
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> >
> > --
> > With Regards,
> > *Jalaj Jaiswal* (+919019947895)
> > Software developer, Cisco Systems
> > B.Tech IIIT ALLAHABAD
>
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