void change()
{
#define i i=10,n
}
this will do..
On Tue, Feb 15, 2011 at 11:33 PM, Rel Guzman Apaza <rgap...@gmail.com>wrote:
> Nothing... 10 in base 5 = 5 in base 10.
>
> void change(){
> printf(""); //...?
> }
>
> 2011/2/15 Don <dondod...@gmail.com>
>
> A semicolon is valid in the middle of a line in C or C++.
>>
>> For instance, no one says that
>>
>> for(i = 0; i < 10; ++i)
>>
>> is three lines of code.
>>
>> Don
>>
>> On Feb 15, 11:31 am, jalaj jaiswal <jalaj.jaiswa...@gmail.com> wrote:
>> > after termination of semicolon , that will be considered a separate line
>> i
>> > guess
>> >
>> >
>> >
>> > On Tue, Feb 15, 2011 at 10:59 PM, Don <dondod...@gmail.com> wrote:
>> > > void change()
>> > > {
>> > > printf("10"); while(1) {}
>> > > }
>> >
>> > > On Feb 15, 10:17 am, Balaji S <balaji.ceg...@gmail.com> wrote:
>> > > > Insert only one line in the function change() so that the output of
>> the
>> > > > program is 10.
>> > > > You are not allowed to use exit(). You are not allowed to edit the
>> > > function
>> > > > main() or to
>> > > > pass the parameter to change()
>> >
>> > > > void change()
>> > > > {
>> > > > // Code here}
>> >
>> > > > int main()
>> > > > {
>> > > > int i=5;
>> > > > change();
>> > > > printf(“%d” ,i);
>> > > > return 0;
>> >
>> > > > }
>> >
>> > > --
>> > > You received this message because you are subscribed to the Google
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>> >
>> > --
>> > With Regards,
>> > *Jalaj Jaiswal* (+919019947895)
>> > Software developer, Cisco Systems
>> > B.Tech IIIT ALLAHABAD
>>
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