The only way to get an acute triangle this way is to connect the diagonals of three adjacent faces. You can select 3 adjacent faces of a cube in (6*4*2)/(3*2*1) = 8 different ways.
Regards Priyaranjan http://code-forum.blogspot.com On Feb 23, 12:10 am, jalaj jaiswal <jalaj.jaiswa...@gmail.com> wrote: > answer is 8 ,,, duno how > > > > > > > > > > On Wed, Feb 23, 2011 at 12:31 AM, Sundi <sundi...@gmail.com> wrote: > > Is it not 8C3 = 56 > > > On Feb 22, 9:55 pm, jalaj jaiswal <jalaj.jaiswa...@gmail.com> wrote: > > > Think of the 8 vertices of a given cube. You are allowed to join three > > > vertices to form a triangle. How many such unique acute triangles can you > > > make ?? > > > > -- > > > With Regards, > > > *Jalaj Jaiswal* (+919019947895) > > > Software developer, Cisco Systems > > > B.Tech IIIT ALLAHABAD > > > -- > > You received this message because you are subscribed to the Google Groups > > "Algorithm Geeks" group. > > To post to this group, send email to algogeeks@googlegroups.com. > > To unsubscribe from this group, send email to > > algogeeks+unsubscr...@googlegroups.com. > > For more options, visit this group at > >http://groups.google.com/group/algogeeks?hl=en. > > -- > With Regards, > *Jalaj Jaiswal* (+919019947895) > Software developer, Cisco Systems > B.Tech IIIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
