@Priyaranjan. Right. I should have directed my comment to Vikas. Sorry. Dave
On Feb 24, 9:35 pm, awesomeandroid <priyaranjan....@gmail.com> wrote: > @dave i never said it will be a right angled triangle ,it will be a > equilateral triangle and thus an acute angled triangle. > > On Feb 24, 8:38 pm, Dave <dave_and_da...@juno.com> wrote: > > > > > @Priyaranjan: Suppose that the cube has side 1 and is placed in > > "standard position at the origin." Then the triangle with vertices > > (0,0,0), (1,0,1), and (1,1,0) is equilateral with side sqrt(2), and > > therefore is not a right triangle. > > > Dave > > > On Feb 24, 8:49 am, Vikas Kumar <dev.vika...@gmail.com> wrote: > > > > @priyaranjan > > > No,Your triangle will be right angle triangle. > > > > In fact any triangle chosen will be right angle triangle. > > > > Proof: > > > > suppose there are 2 planes kept at parallel with each other.(top bottom) > > > join corresponding vertices of up to down and form cube. > > > > Now 3 points chosen can be on same plane .(means 2 must be adjacent) > > > so right angle triangle is only possible > > > > or at least 2 points are on same plane and 3rd point is other plane(pigeon > > > hole as only 2 holes are there for 3 pegions) > > > > Now as 3 rd point always lies on perpendicular point so triagle formed > > > will > > > always be right angled. > > > > On Thu, Feb 24, 2011 at 5:23 PM, awesomeandroid > > > <priyaranjan....@gmail.com>wrote: > > > > > The only way to get an acute triangle this way is to connect the > > > > diagonals of three adjacent faces. You can select 3 adjacent faces of > > > > a cube in (6*4*2)/(3*2*1) = 8 different ways. > > > > > Regards > > > > Priyaranjan > > > >http://code-forum.blogspot.com > > > > > On Feb 23, 12:10 am, jalaj jaiswal <jalaj.jaiswa...@gmail.com> wrote: > > > > > answer is 8 ,,, duno how > > > > > > On Wed, Feb 23, 2011 at 12:31 AM, Sundi <sundi...@gmail.com> wrote: > > > > > > Is it not 8C3 = 56 > > > > > > > On Feb 22, 9:55 pm, jalaj jaiswal <jalaj.jaiswa...@gmail.com> wrote: > > > > > > > Think of the 8 vertices of a given cube. You are allowed to join > > > > three > > > > > > > vertices to form a triangle. How many such unique acute triangles > > > > > > > can > > > > you > > > > > > > make ?? > > > > > > > > -- > > > > > > > With Regards, > > > > > > > *Jalaj Jaiswal* (+919019947895) > > > > > > > Software developer, Cisco Systems > > > > > > > B.Tech IIIT ALLAHABAD > > > > > > > -- > > > > > > You received this message because you are subscribed to the Google > > > > Groups > > > > > > "Algorithm Geeks" group. > > > > > > To post to this group, send email to algogeeks@googlegroups.com. > > > > > > To unsubscribe from this group, send email to > > > > > > algogeeks+unsubscr...@googlegroups.com. > > > > > > For more options, visit this group at > > > > > >http://groups.google.com/group/algogeeks?hl=en. > > > > > > -- > > > > > With Regards, > > > > > *Jalaj Jaiswal* (+919019947895) > > > > > Software developer, Cisco Systems > > > > > B.Tech IIIT ALLAHABAD > > > > > -- > > > > You received this message because you are subscribed to the Google > > > > Groups > > > > "Algorithm Geeks" group. > > > > To post to this group, send email to algogeeks@googlegroups.com. > > > > To unsubscribe from this group, send email to > > > > algogeeks+unsubscr...@googlegroups.com. > > > > For more options, visit this group at > > > >http://groups.google.com/group/algogeeks?hl=en.-Hidequoted text - > > > > - Show quoted text -- Hide quoted text - > > - Show quoted text - -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
