How do Levenshtein distance used.. For that u need to know the palindrome
that is closest to it.. and if that is know than there is no point in
calculating the distance .. we can easily see how many changes are to be
made..!(correct me if I am wrong)

Further my approach is this :
taking the number in a string and then I can find the mid point of it. (for
an even number  digit i have 2 mid points). Now i can move one pointer to
the left and other to the right to check whether there is a match in the
string , if not i increase the value of cntr by 1
For eg
98099
mid is '0' so mantain to pointers and see that 8!=9 hence cntr+1
next 9=9 . and we reach the end .
hence answer is 1.

On Thu, Feb 24, 2011 at 7:36 PM, Balaji S <balaji.ceg...@gmail.com> wrote:

> how to solve it using DP??
>
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