It can be done without sorting. Take the first element as pivot element. Calculate its position using Partition algorithm. If its new index is K, then on left side are top K integers. If index>K, apply algo on left side Else apply algo on right side.
Best Case: O(1) Worst Case: O(n^2) But there are very less chances of worst case. It is when the list is already sorted. On Thu, May 5, 2011 at 1:06 AM, amit <amitjaspal...@gmail.com> wrote: > Hi , > > We are give a list of integers now our task is to find the top K > integers in the list based on frequency. > > Apart from sorting the data can there be any other algorithm? > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- Gaurav Aggarwal SCJP -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
