@Dave: Can there be an in-place O(n) solution to this???

On Mon, May 9, 2011 at 7:01 PM, Dave <dave_and_da...@juno.com> wrote:

> @Ashish: By compress, I meant to transfer the active entries in the
> hash table into contiguous elements of an array. Since the hash table
> itself is probably stored in an array, it just means to go through the
> hash table array and move the active entries to the front of the
> array.
>
> Dave
>
> On May 9, 1:14 am, Ashish Goel <ashg...@gmail.com> wrote:
> > Dave,
> > w.r.t statement, After all integers are processed, compress out the
> unused
> > hash table
> > entries and find the Kth largest element,
> >
> > I could not understand the compress concept...are you saying something on
> > counting sort philosophy?
> > say the list is
> >
> > 5
> > 4
> > 4
> > 3
> > 3
> > 3
> > 2
> > 2
> > 2
> > 2
> > 1
> > 1
> > 1
> > 1
> > 1
> >
> > so the hash map will have
> >
> > 5,1 <5 is 1 time>
> > 4,2,<4 is two time>
> > 3,3,...
> > 2,4,...
> > 1,5...
> >
> > so if the question is to find say 3rd largest element based on frequency,
> it
> > would be 4
> > This essentially means that we probably need dynamic order statistics
> where
> > the node contains the starting rank for a particular entry in the RBTree.
> > Each RBTree node contains the number, its frequency and rank. then this
> > becomes O(n) +O(lgn) i.e. O(n)
> >
> > Best Regards
> > Ashish Goel
> > "Think positive and find fuel in failure"
> > +919985813081
> > +919966006652
> >
> >
> >
> > On Sat, May 7, 2011 at 11:03 PM, Dave <dave_and_da...@juno.com> wrote:
> > > @Gaurav: As I understand your solution, you are finding the K largest
> > > integers based on value, rather than the K with the highest frequency
> > > of occurrence.
> >
> > > @Amit: Hash the integers into a hash table that includes a field for
> > > the frequency count. When a new entry is made, set the frequency count
> > > to 1. When an integer already is in the table, increment its count.
> > > After all integers are processed, compress out the unused hash table
> > > entries and find the Kth largest element. The overall algorithm can be
> > > done in O(n).
> >
> > > Dave
> >
> > > On May 7, 12:06 pm, Gaurav Aggarwal <0007gau...@gmail.com> wrote:
> > > > It can be done without sorting. Take the first element as pivot
> > > > element. Calculate its position using Partition algorithm.
> > > > If its new index is K, then on left side are top K  integers. If
> index>K,
> > > > apply algo on left side Else apply algo on right side.
> >
> > > > Best Case: O(1)
> > > > Worst Case: O(n^2)
> >
> > > > But there are very less chances of worst case. It is when the list is
> > > > already sorted.
> >
> > > > On Thu, May 5, 2011 at 1:06 AM, amit <amitjaspal...@gmail.com>
> wrote:
> > > > > Hi ,
> >
> > > > > We are give a list of integers now our task is to find the top K
> > > > > integers in the list based on frequency.
> >
> > > > > Apart from sorting the data can there be any other algorithm?
> >
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> > > > --
> > > > Gaurav Aggarwal
> > > > SCJP- Hide quoted text -
> >
> > > > - Show quoted text -
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-- 
regards

Apoorve Mohan

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