@Aamir: No, it won't overflow. The maximum double is approximately
10^307.95. His value is well within the range of doubles. The problem
is that doubles don't have enough precision. See my preceding post for
an explanation.
Dave
On May 13, 6:42 am, Aamir Khan <ak4u2...@gmail.com> wrote:
> double n will overflow...
>
> On 5/13/11, bittu <shashank7andr...@gmail.com> wrote:
>
>
>
>
>
> > @Dave... I think 1 Googol Year is =10^100 not 10^116.5 ?? why u have
> > used
>
> > so then we have to write the single line program that googol years of
> > time ?? & we have processor that can execute the instruction in 10^9
> > per second so the time required by googol year in second
> > which is equals to time t=pow(10,109)*365*86400 sec.
>
> > so program is like
>
> > #include <stdio.h>
> > #include <math.h>
>
> > int main() {
>
> > double n = pow(10, 109) * 365 * 86400;
>
> > while(n--);
> > }
>
> > Correct me if anything wrong???
>
> > Thanks & Regards
> > Shashank Mani>>"The Best Way To Escape From The problem is Solve It"
> > Computer Science & Engg.
> > BIT Mesra
>
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> --
> Aamir Khan
> Indian Institute of Technology Roorkee,
> Roorkee, Uttarakhand,
> India , 247667
> Phone: +91 9557647357
> email: aami...@iitr.ernet.in <aamir...@iitr.ernet.in>
> ak4u2...@gmail.com- Hide quoted text -
>
> - Show quoted text -
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