@aakash
the cases are clear but can you explain how you did the matrix
exponentiation part ??......explain plz...i'm not getting it...

On Tue, May 24, 2011 at 1:25 AM, Aakash Johari <aakashj....@gmail.com>wrote:

> It's done. Today I tried it.
>
> Simply for N=0 and N=1 answer is (0,0) = 0 and (1,1)=2 respectively.
>
> For other cases, you can get the solution with fib(N+3). Starting fib(1) =
> 1, fib(2) = 1...
>
> Matrix Exponentiation, and Modulus for given constraints are necessary to
> pass the solution.
>
>
>
> On Mon, May 23, 2011 at 11:58 PM, sravanreddy001 <sravanreddy...@gmail.com
> > wrote:
>
>> @Dave,Balaji,Samby.. Without the matrix exponentiation, the time is not
>> possible, and without using the intermediate modulo operater as suggested by
>> Dave, the value cannot be accommodated, as the 300th fibinocci number alone
>> comes to
>> --> 222232244629420445529739893461909967206666939096499764990979600
>> So, a mix of both are needed.. I'll try to look into this.
>>
>> any alternate solution you can think of?
>>
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>
>
>
> --
> -Aakash Johari
> (IIIT Allahabad)
>
>
>
>
>
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