@Sanjay ahuja
yes ans is required in O(n)
how it can be done by hashing?

On Fri, Jun 3, 2011 at 1:19 AM, Supraja Jayakumar
<suprajasank...@gmail.com>wrote:

> Hi
>
> I think multi hash table will solve this problem.
>
> Thanks
> Supraja J
>
>
> On Thu, Jun 2, 2011 at 1:37 PM, Harshal <hc4...@gmail.com> wrote:
>
>> But I think the solution required is O(n) (one pass). So, O(nlogn) is not
>> what the author wants anyway. Hashing is an option but we dont know the
>> range of the elements in the array. So, in case when all keys hash into the
>> same place, the worst case is still O(n^2).
>> suppose our hash function is h(n) = n mod 10.
>> array: 2,12,32,52,42.
>>
>>
>>
>> On Fri, Jun 3, 2011 at 1:01 AM, Harshal <hc4...@gmail.com> wrote:
>>
>>> you can check if the element to be inserted next is same as the node
>>> value while inserting itself. Why to do a separate inorder traversal..
>>>
>>>
>>> On Fri, Jun 3, 2011 at 12:56 AM, Supraja Jayakumar <
>>> suprajasank...@gmail.com> wrote:
>>>
>>>> Hi
>>>>
>>>> Inserting into BST and break on same element will detect duplicates.
>>>> But in any case, this is still O(2n) ? - once for inserting them in to
>>>> the tree
>>>> and another for the inorder read.
>>>>
>>>> Correct me if wrong.
>>>>
>>>> Rgds
>>>> Supraja J
>>>>
>>>>
>>>> On Thu, Jun 2, 2011 at 1:11 PM, Harshal <hc4...@gmail.com> wrote:
>>>>
>>>>> @Anurag: XOR wont work here, 1 element is repeated, not 1 element is
>>>>> unique. Read the question again.
>>>>>
>>>>> Keep inserting elements in a BST and break once you find the same
>>>>> element. O(nlogn)
>>>>>
>>>>>
>>>>> On Fri, Jun 3, 2011 at 12:38 AM, Anurag Narain <anuragnar...@gmail.com
>>>>> > wrote:
>>>>>
>>>>>> take X-OR of all the elements.....the one which has no duplicate will
>>>>>> be left and rest all will be reduced to zero.
>>>>>>
>>>>>>  --
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>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> Harshal Choudhary,
>>>>> III Year B.Tech CSE,
>>>>> NIT Surathkal, Karnataka, India.
>>>>>
>>>>>
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>>>>
>>>>
>>>>
>>>> --
>>>> U
>>>>
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>>>
>>>
>>>
>>> --
>>> Harshal Choudhary,
>>> III Year B.Tech CSE,
>>> NIT Surathkal, Karnataka, India.
>>>
>>>
>>>
>>
>>
>> --
>> Harshal Choudhary,
>> III Year B.Tech CSE,
>> NIT Surathkal, Karnataka, India.
>>
>>
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>
>
>
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> U
>
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-- 
**With Regards
Deoki Nandan Vishwakarma
IITR MCA
Mathematics Department*
*

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