ignore above solution. My bad, did'nt see O(1) space constraint!! On Wed, Jun 22, 2011 at 10:53 AM, Harshal <hc4...@gmail.com> wrote:
> You can make use of an auxiliary array(initialized to 0) to store the count > of each char and then print it that many times. > char inp[]="abcdaabcdefe"; > int buff[256]={0}; > > for(int i=0;i<strlen(inp);i++) > buff[inp[i]]++; > > for(int j=0;j<256;j++) > while(buff[j]--) cout<<(char)j; > > On Wed, Jun 22, 2011 at 10:27 AM, Sriganesh Krishnan <2448...@gmail.com>wrote: > >> Input will be a string. We need to o/p a string with the order of >> characters same as the input but with same characters grouped together. >> I/P: abcdacde >> O/P: aabccdde >> >> I/P: kapilrajadurga >> O/P: kaaaapilrrjdug >> >> I/P: 1232 >> O/P: 1223 ……………….. O(n) time……….. O(1) space……………. >> >> >> how can you approach these type of string related problems, is there any >> specific technique involved? >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > Harshal Choudhary, > Final Year B.Tech CSE, > NIT Surathkal, Karnataka, India. > > > -- Harshal Choudhary, Final Year B.Tech CSE, NIT Surathkal, Karnataka, India. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.