No, it will not work. We don't have to print all the characters in sorted
order.

On Thu, Jun 23, 2011 at 12:19 AM, snehi jain <snehijai...@gmail.com> wrote:

> what if we create a binary tree with root as the first element of the
> string and if the next character is equal then place it to left else place
> it to right. Similar comparison will be done while inserting all the other
> nodes too .
>
> after that if InOrder traversal is performed.. it would give us the desired
> output.
>
> i didnt code it ... but it sounds ok to me..
> correct me if i am wrong ..
>
>
> Snehi
>
>
> On Wed, Jun 22, 2011 at 9:48 PM, DK <divyekap...@gmail.com> wrote:
>
>> No. This is equivalent to a sort with comparisons based on index of first
>> occurrence in the input string. Any comparative algorithm is O(n log n) and
>> a non comparative algorithm can be O(n) only by using counting or radix
>> sorting etc.
>>
>> --
>> DK
>>
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>> http://www.divye.in
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