Let the array elements be 2,3,5,10 & 1,4,8,12.

Have two index variables m and n. Intially m will point to 2 and n to 1.

1. Compare the elements in m and n.
2. If elem[m] > elem[n] swap, increment n
3. else increment m and go to step 1.
4. end if m becomes the starting value of n or n reaches end of array.

Think it should work.

On Wed, Jun 22, 2011 at 4:05 PM, Algoose chase <harishp...@gmail.com> wrote:
> Reverse the 2nd part of the Array so that they are sorted in descending
> order.
> Then apply bitonic sort
> On Wed, Jun 22, 2011 at 2:34 PM, ross <jagadish1...@gmail.com> wrote:
>>
>> @himanshu: I dont think, the approach works, in present form.
>> in place merge sort or  insertion sort is fine.
>> Test with,  12 13 19 16 and 0 20 10 14 as 2 parts of the array.
>>
>> On Jun 22, 8:42 am, Sriganesh Krishnan <2448...@gmail.com> wrote:
>> > ya...we can do it in O(n) n time!!!
>> > nice question!
>> >
>> > On Tue, Jun 21, 2011 at 11:01 PM, himanshu kansal <
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> > himanshukansal...@gmail.com> wrote:
>> > > @anika: yar merge sort vl tk nlogn time....instead u cn do dt maintain
>> > > two
>> > > ptrs one at the beginning and one intitially pointing to middle of the
>> > > array...
>> > > thn compare the elemnts pointed by them and swap the values if
>> > > necesary nd
>> > > incremnt d ptr as u go on...
>> > > ths vl tk (n/2)+(n/2)-1 =O(n) time....
>> > > corrct me if m wrong....
>> >
>> > > On Tue, Jun 21, 2011 at 10:56 PM, Anika Jain
>> > > <anika.jai...@gmail.com>wrote:
>> >
>> > >> its like inplace mergesort
>> >
>> > >> On Tue, Jun 21, 2011 at 10:13 PM, aanchal goyal
>> > >> <goyal.aanch...@gmail.com
>> > >> > wrote:
>> >
>> > >>> you have an array of size n where first n/2 is sorted and the
>> > >>> sencond
>> > >>> half is sorted . You need to sort the entire array inplace
>> > >>> Its second modification version is where first part is sorted and
>> > >>> other
>> > >>> is NOT sorted . You need to make entire sorted .
>> >
>> > >>> --
>> > >>> Regards,*
>> > >>> Aanchal Goyal*.
>> >
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>> > > --
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>> > >       Regards
>> > > Himanshu Kansal
>> > >   Msc Comp. sc.
>> > > (University of Delhi)
>> >
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--Navneet

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