This problem can also be done by using Merging function as in the merge sort. 1. Copy the sorted elements of the first half in one array (arr L) and second half in another (arr R). Original array N. 2. count vary from 1 to n.
if (L[i] < R[j] ) { N[count] = L[i], i++} else { N[count] = R[j] , j++} count++ 3. copy the rest of the elements from the remaining (either L or R whichever is remaining) Time complexity O(n) Plz correct me if I m wrong. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.