Okay, I found the problem i think,
(x > 10) ? y++: x = 10 is evaluated as ((x > 10) ? y++: x) = 10
which is wrong..
(x > 10) ? y++: (x = 10) will work.
On Fri, Jun 24, 2011 at 9:22 AM, Vishal Thanki <vishaltha...@gmail.com> wrote:
> yes, i understand that.. but is there any limitation in ternary
> operator that the 2nd expression (after ":")should not use assignment
> operator?
>
>
>
> On Fri, Jun 24, 2011 at 9:21 AM, Wladimir Tavares <wladimir...@gmail.com>
> wrote:
>> Try this:
>> #include <stdio.h>
>> #include <stdlib.h>
>> int main(int argc, char *argv[])
>> {
>> int x = atoi(argv[1]);
>> int y = 10;
>> x = (x > 10) ? y++: 10;
>> return x;
>> }
>> Wladimir Araujo Tavares
>> Federal University of Ceará
>>
>>
>>
>>
>>
>>
>> On Fri, Jun 24, 2011 at 12:40 AM, Vishal Thanki <vishaltha...@gmail.com>
>> wrote:
>>>
>>> Hey all,
>>>
>>> I think I am missing something very basic in C, and which is troubling
>>> me. Following code is not compiling for me, can anyone explain why?
>>>
>>> vishal@ubuntu:~/progs/c\ 09:07:01 AM >$ cat ternary.c
>>> #include <stdio.h>
>>> #include <stdlib.h>
>>> int main(int argc, char *argv[])
>>> {
>>> int x = atoi(argv[1]);
>>> int y = 10;
>>> (x > 10) ? y++: x = 10;
>>> return x;
>>> }
>>> vishal@ubuntu:~/progs/c\ 09:07:08 AM >$ gcc ternary.c
>>> ternary.c: In function ‘main’:
>>> ternary.c:7: error: lvalue required as left operand of assignment
>>>
>>>
>>> Vishal
>>>
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