When we declare *char *str="hello";* this "hello" will be stored in the read-only memory i.e *TEXT Segment*.
so when we try to write the read-only memory by **str='w';* it will throw *Segmentation fault*. Obviously we must allocate some memory in heap to modify it like: *char *str=(char *)malloc(1024);* Thanks & Regards, Anantha Krishnan On Sat, Jun 25, 2011 at 2:16 PM, Adarsh <s.adars...@gmail.com> wrote: > char array[] = "hello"; > char *pointer = "hello"; > > array is an array, enough to store sequence of characters and '\0' > array will always refer to same storage. > Here, pointer is initialized to point to a string constant, pointer > may be modified, but you cannot chage string contents > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
