Thanks all :).

On 6/25/11, Anantha Krishnan <ananthakrishnan....@gmail.com> wrote:
> When we declare *char *str="hello";*
>
> this "hello" will be stored in the read-only memory i.e *TEXT Segment*.
>
> so when we try to write the read-only memory by **str='w';* it will
> throw *Segmentation
> fault*.
>
> Obviously we must allocate some memory in heap to modify it like:
> *char *str=(char *)malloc(1024);*
>
> Thanks & Regards,
> Anantha Krishnan
>
> On Sat, Jun 25, 2011 at 2:16 PM, Adarsh <s.adars...@gmail.com> wrote:
>
>> char array[] = "hello";
>> char *pointer = "hello";
>>
>> array is an array, enough to store sequence of characters and '\0'
>> array will always refer to same storage.
>> Here, pointer is initialized to point to a string constant, pointer
>> may be modified, but you cannot chage string contents
>>
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