how about converting the BST into a doubly linked list...but this will
definitely modify the BST..

On Mon, Jun 27, 2011 at 11:32 PM, Swathi <chukka.swa...@gmail.com> wrote:

> Dave,
>
> I am unable to write code for this so i am asking your help.
>
> Thanks,
> Swathi
>
>
> On Mon, Jun 27, 2011 at 11:28 PM, Dave <dave_and_da...@juno.com> wrote:
>
>> @Swathi: No. I think the high level description should be adequate for
>> you to write your own code or pseudocode, albeit recognizing that you
>> may have to look up how to do an inorder traversal using a stack
>> instead of recursion.
>>
>> Dave
>>
>> On Jun 27, 9:34 am, Swathi <chukka.swa...@gmail.com> wrote:
>> > Dave,
>> >
>> > Can you provide the psuedo code for this..
>> >
>> > Thanks,
>> > Swathi
>> >
>> >
>> >
>> > On Mon, Jun 27, 2011 at 7:30 PM, Dave <dave_and_da...@juno.com> wrote:
>> > > @Sunny. Mea culpa. You are correct. Revised (and correct) algorithm.
>> > > Do two inorder traversals, one in the usual (descend to the left
>> > > before descendung to the right) direction and the other in the
>> > > reversed(descend to the right before descending to the left)
>> > > direction. Let u and r be the current nodee of the two traversals,
>> > > respectively. If u + r < x, then advance the usual traversal and
>> > > repeat the comparison. If u + r > x, advance the reverse traversal and
>> > > repeat the comparison. If u + r = x, and if u != r, then terminate
>> > > with success. If u = r, then terminate with failure.
>> >
>> > > Dave
>> >
>> > > On Jun 27, 7:53 am, sunny agrawal <sunny816.i...@gmail.com> wrote:
>> > > > @Dave
>> > > > i think your solution won't work
>> > > > consider inorder traversal of a BST is 1 6 7 8 15 and x = 14
>> > > > initially both u,v (1,1)
>> > > > according to u your algorithm will proceed like
>> > > > (1,1) -> (1,6) -> (1,7) -> (1,8) -> (1,15) -> (6,15) ............ ->
>> > > (15,15)
>> >
>> > > > and clearly in second step of your solution if (u+v) > x after
>> advancing
>> > > u
>> > > > still u+v will be greater than x
>> > > > so something is wrong
>> > > > I think your solution will work in case we need to find 2 nodes with
>> > > > difference x.
>> >
>> > > > correct me if i am wrong.!!
>> >
>> > > > On Mon, Jun 27, 2011 at 6:13 PM, Dave <dave_and_da...@juno.com>
>> wrote:
>> > > > > @Nishant: No need to store the data in an array. Do two inorder
>> > > > > traversals simultaneously. Let u and v be the current nodes of the
>> two
>> > > > > traversals, respectively. If u + v < x, then advance the "v"
>> > > > > traversal. If u + v > x, advance the "u" traversal.
>> >
>> > > > > Dave
>> >
>> > > > > On Jun 27, 3:40 am, Nishant Mittal <mittal.nishan...@gmail.com>
>> wrote:
>> > > > > > do inorder traversal of tree and store values in an array.
>> > > > > > Now find pairs by applying binary search on array..
>> >
>> > > > > > On 6/27/11, manish kapur <manishkapur.n...@gmail.com> wrote:
>> >
>> > > > > > > --
>> > > > > > > You received this message because you are subscribed to the
>> Google
>> > > > > Groups
>> > > > > > > "Algorithm Geeks" group.
>> > > > > > > To post to this group, send email to
>> algogeeks@googlegroups.com.
>> > > > > > > To unsubscribe from this group, send email to
>> > > > > > > algogeeks+unsubscr...@googlegroups.com.
>> > > > > > > For more options, visit this group at
>> > > > > > >http://groups.google.com/group/algogeeks?hl=en.-Hidequotedtext -
>> >
>> > > > > > - Show quoted text -
>> >
>> > > > > --
>> > > > > You received this message because you are subscribed to the Google
>> > > Groups
>> > > > > "Algorithm Geeks" group.
>> > > > > To post to this group, send email to algogeeks@googlegroups.com.
>> > > > > To unsubscribe from this group, send email to
>> > > > > algogeeks+unsubscr...@googlegroups.com.
>> > > > > For more options, visit this group at
>> > > > >http://groups.google.com/group/algogeeks?hl=en.
>> >
>> > > > --
>> > > > Sunny Aggrawal
>> > > > B-Tech IV year,CSI
>> > > > Indian Institute Of Technology,Roorkee- Hide quoted text -
>> >
>> > > > - Show quoted text -
>> >
>> > > --
>> > > You received this message because you are subscribed to the Google
>> Groups
>> > > "Algorithm Geeks" group.
>> > > To post to this group, send email to algogeeks@googlegroups.com.
>> > > To unsubscribe from this group, send email to
>> > > algogeeks+unsubscr...@googlegroups.com.
>> > > For more options, visit this group at
>> > >http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text -
>> >
>> > - Show quoted text -
>>
>> --
>> You received this message because you are subscribed to the Google Groups
>> "Algorithm Geeks" group.
>> To post to this group, send email to algogeeks@googlegroups.com.
>> To unsubscribe from this group, send email to
>> algogeeks+unsubscr...@googlegroups.com.
>> For more options, visit this group at
>> http://groups.google.com/group/algogeeks?hl=en.
>>
>>
>  --
> You received this message because you are subscribed to the Google Groups
> "Algorithm Geeks" group.
> To post to this group, send email to algogeeks@googlegroups.com.
> To unsubscribe from this group, send email to
> algogeeks+unsubscr...@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/algogeeks?hl=en.
>



-- 
*Piyush Sinha*
*IIIT, Allahabad*
*+91-8792136657*
*+91-7483122727*
*https://www.facebook.com/profile.php?id=100000655377926 *

-- 
You received this message because you are subscribed to the Google Groups 
"Algorithm Geeks" group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.

Reply via email to