ohh sorry....my bad...i didnt read the whole question..i just read the
subject...:P
i think its not possible if u want other than hary's solution...
On 6/30/11, Apoorve Mohan <apoorvemo...@gmail.com> wrote:
> @piyush: only one call to malloc...ur sol has 2
>
> On Thu, Jun 30, 2011 at 12:58 AM, Piyush Sinha
> <ecstasy.piy...@gmail.com>wrote:
>
>> int **p;
>> p = (int **)malloc(sizeof(int *)*row);
>> for(i = 0;i<row;i++)
>> p[i] = (int *)malloc(sizeof(int)*column);
>>
>> On 6/30/11, Apoorve Mohan <apoorvemo...@gmail.com> wrote:
>> > though thankx :)
>> >
>> > On Thu, Jun 30, 2011 at 12:44 AM, Apoorve Mohan
>> > <apoorvemo...@gmail.com>wrote:
>> >
>> >> @above: man i need a 2d array not a 1d array...
>> >>
>> >>
>> >> On Thu, Jun 30, 2011 at 12:38 AM, hary rathor
>> >> <harry.rat...@gmail.com>wrote:
>> >>
>> >>>
>> >>> #include<stdlib.h>
>> >>>
>> >>> int main ()
>> >>> {
>> >>> int *mat;
>> >>> int i,j;
>> >>> int ROW=4;
>> >>> int COL=3;
>> >>> int k=0;
>> >>> mat=(int *)malloc(ROW*COL*sizeof(int));
>> >>>
>> >>> for(i=0;i<ROW;i++)
>> >>> for(j=0;j<COL;j++)
>> >>> mat[i*COL+j]=++k;
>> >>>
>> >>> for(i=0;i<ROW;i++)
>> >>> for(j=0;j<COL;j++)
>> >>> printf("%d,",mat[i*COL+j]);
>> >>>
>> >>> return 0;
>> >>>
>> >>> }
>> >>>
>> >>>
>> >>>
>> >>> --
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>> >>
>> >>
>> >>
>> >> --
>> >> regards
>> >>
>> >> Apoorve Mohan
>> >>
>> >>
>> >
>> >
>> > --
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>> >
>> > Apoorve Mohan
>> >
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>>
>> --
>> *Piyush Sinha*
>> *IIIT, Allahabad*
>> *+91-8792136657*
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>
>
> --
> regards
>
> Apoorve Mohan
>
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--
*Piyush Sinha*
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