do we need to add m in each a[i]?? shudnt it be a[i] = a+ n*i?? i think i m
doing a silly mistake.. bt plz tell me..
On Thu, Jun 30, 2011 at 7:41 AM, Dave <dave_and_da...@juno.com> wrote:
> @Rizwan: Not completely. What if ROW in your code is a variable (not a
> constant) that is not known until run time? Then you need to
> dynamically allocate space for your arr2D as well. So, contradicting
> my earlier "No" response, maybe something like this would work to
> allocate an array a with m rows and n columns:
>
> int* a = (int*)malloc( m * ( sizeof(int*) + n * sizeof(int) ) );
> for( i = 0 ; i < m ; ++i )
> a[i] = a + m + i * n;
>
> Dave
>
> On Jun 29, 4:41 pm, rizwan hudda <rizwanhu...@gmail.com> wrote:
> > I have solved this using one malloc find the code inhttp://
> ideone.com/BV9Kj
> >
> >
> >
> >
> >
> > On Thu, Jun 30, 2011 at 1:20 AM, Piyush Sinha <ecstasy.piy...@gmail.com>
> wrote:
> > > ohh sorry....my bad...i didnt read the whole question..i just read the
> > > subject...:P
> >
> > > i think its not possible if u want other than hary's solution...
> >
> > > On 6/30/11, Apoorve Mohan <apoorvemo...@gmail.com> wrote:
> > >> @piyush: only one call to malloc...ur sol has 2
> >
> > >> On Thu, Jun 30, 2011 at 12:58 AM, Piyush Sinha
> > >> <ecstasy.piy...@gmail.com>wrote:
> >
> > >>> int **p;
> > >>> p = (int **)malloc(sizeof(int *)*row);
> > >>> for(i = 0;i<row;i++)
> > >>> p[i] = (int *)malloc(sizeof(int)*column);
> >
> > >>> On 6/30/11, Apoorve Mohan <apoorvemo...@gmail.com> wrote:
> > >>> > though thankx :)
> >
> > >>> > On Thu, Jun 30, 2011 at 12:44 AM, Apoorve Mohan
> > >>> > <apoorvemo...@gmail.com>wrote:
> >
> > >>> >> @above: man i need a 2d array not a 1d array...
> >
> > >>> >> On Thu, Jun 30, 2011 at 12:38 AM, hary rathor
> > >>> >> <harry.rat...@gmail.com>wrote:
> >
> > >>> >>> #include<stdlib.h>
> >
> > >>> >>> int main ()
> > >>> >>> {
> > >>> >>> int *mat;
> > >>> >>> int i,j;
> > >>> >>> int ROW=4;
> > >>> >>> int COL=3;
> > >>> >>> int k=0;
> > >>> >>> mat=(int *)malloc(ROW*COL*sizeof(int));
> >
> > >>> >>> for(i=0;i<ROW;i++)
> > >>> >>> for(j=0;j<COL;j++)
> > >>> >>> mat[i*COL+j]=++k;
> >
> > >>> >>> for(i=0;i<ROW;i++)
> > >>> >>> for(j=0;j<COL;j++)
> > >>> >>> printf("%d,",mat[i*COL+j]);
> >
> > >>> >>> return 0;
> >
> > >>> >>> }
> >
> > >>> >>> --
> > >>> >>> You received this message because you are subscribed to the
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> > >>> >> --
> > >>> >> regards
> >
> > >>> >> Apoorve Mohan
> >
> > >>> > --
> > >>> > regards
> >
> > >>> > Apoorve Mohan
> >
> > >>> > --
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> > >>> --
> > >>> *Piyush Sinha*
> > >>> *IIIT, Allahabad*
> > >>> *+91-8792136657*
> > >>> *+91-7483122727*
> > >>> *https://www.facebook.com/profile.php?id=100000655377926*
> >
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> >
> > >> --
> > >> regards
> >
> > >> Apoorve Mohan
> >
> > >> --
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> >
> > > --
> > > *Piyush Sinha*
> > > *IIIT, Allahabad*
> > > *+91-8792136657*
> > > *+91-7483122727*
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> > --
> > Thanks and regards
> > Rizwan A Huddahttp://sites.google.com/site/rizwanhudda2- Hide quoted
> text -
> >
> > - Show quoted text -
>
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