This happens because the Derived class's member *hides* the base class's
member.
Irrespective of the number/type of parameters.
The solution to solve this problem is to either add an using declaration in
the derived class.
e.g. *using A::f;*
this will bring f(int) of class A within the scope of class B, and thus
allowing the overload to work
or you need to use the scope resolution operator to explicitly call class
A's hidden function.
e.g. *b.A::f(4);*
Hope this helps.
Regards,
Sandeep Jain
Member of Technical Staff, Adobe Systems, India
On Mon, Jul 4, 2011 at 12:42 PM, himanshu kansal <
himanshukansal...@gmail.com> wrote:
> class A
> { public:
> void g(int i)
> { cout<<"in a";
> }
> };
> class B:public A
> { public:
> void f()
> { cout<<"in b";
> }
> };
> int main()
> { B b;
> b.f(); //vl call b::f()
> b.g(4); //vl call a::g()
> }
>
> but
> class A
> { public:
> void f(int i)
> { cout<<"in a";
> }
> };
> class B:public A
> { public:
> void f()
> { cout<<"in b";
> }
> };
> int main()
> { B b;
> b.f(); //vl call b::f()
> b.f(4); //bt here errror occurs not a matching protoype...
> }
>
> my ques is that cant we overload function in inheritance(which vary in
> parameters)..???
>
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