Thanku sir...:)
On Mon, Jul 4, 2011 at 1:59 PM, Sandeep Jain <sandeep6...@gmail.com> wrote:
> This happens because the Derived class's member *hides* the base class's
> member.
> Irrespective of the number/type of parameters.
> The solution to solve this problem is to either add an using declaration in
> the derived class.
> e.g. *using A::f;*
> this will bring f(int) of class A within the scope of class B, and thus
> allowing the overload to work
> or you need to use the scope resolution operator to explicitly call class
> A's hidden function.
> e.g. *b.A::f(4);*
>
> Hope this helps.
>
>
> Regards,
> Sandeep Jain
> Member of Technical Staff, Adobe Systems, India
>
>
>
>
> On Mon, Jul 4, 2011 at 12:42 PM, himanshu kansal <
> himanshukansal...@gmail.com> wrote:
>
>> class A
>> { public:
>> void g(int i)
>> { cout<<"in a";
>> }
>> };
>> class B:public A
>> { public:
>> void f()
>> { cout<<"in b";
>> }
>> };
>> int main()
>> { B b;
>> b.f(); //vl call b::f()
>> b.g(4); //vl call a::g()
>> }
>>
>> but
>> class A
>> { public:
>> void f(int i)
>> { cout<<"in a";
>> }
>> };
>> class B:public A
>> { public:
>> void f()
>> { cout<<"in b";
>> }
>> };
>> int main()
>> { B b;
>> b.f(); //vl call b::f()
>> b.f(4); //bt here errror occurs not a matching protoype...
>> }
>>
>> my ques is that cant we overload function in inheritance(which vary in
>> parameters)..???
>>
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--
Regards
Himanshu Kansal
Msc Comp. sc.
(University of Delhi)
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