probability that i win standing at second position: 1/365
probability that i win standing at third position : 364/365*2/365 =
1/365)*(628/365)
probability that i win standing at fourth position : 364/365*363/365*3/365
probability that i win standing at 4th position :
364/365*363/365*362/365*4/365
probability that i win standing at (n+1)th position:
(365-1)*(365-2)*(365-3)*(365-4)*(365-5).....*(365-(n-2))*(365-(n-1))*(n)*(1/365)^n
there is a pattern in the probabilities
let probability of winning standing at nth position be x
probability of winning standing at (n+1)th position = x * {(365 - n +1)*(n)}
/ {365*(n-1)}
maximum probability is at nth position if at (n+1)th position,
{(365 - n +1)*(n)} / {365*(n-1)}
--
Tushar Bindal
Computer Engineering
Delhi College of Engineering
Mob: +919818442705
E-Mail : tushicom...@gmail.com
Website: www.jugadengg.com
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