Sory once again for that incomplete answer.
The complete one is here.
probability that i win standing at second position: 1/365
probability that i win standing at third position : 364/365*2/365 =
1/365)*(628/365)
probability that i win standing at fourth position : 364/365*363/365*3/365
probability that i win standing at 4th position :
364/365*363/365*362/365*4/365
probability that i win standing at (n+1)th position:
(365-1)*(365-2)*(365-3)*(365-
4)*(365-5).....*(365-(n-2))*(365-(n-1))*(n)*(1/365)^n
there is a pattern in the probabilities
let probability of winning standing at nth position be x
probability of winning standing at (n+1)th position = x * {(365 - n +1)*(n)}
/ {365*(n-1)}
maximum probability is at nth position if at (n+1)th position,
{(365 - n +1)*(n)} / {365*(n-1)} <= 1
This is true for n>=20
For n=19,
{(365 - n +1)*(n)} / {365*(n-1)} > 1
So max probability is when *n=19*
i.e., n+1 = 20, which is my position.
So standing at 20th position gives me maximum chance of winning
Just hope I haven't got anything wrong here.
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