we are basically assigning address value "a" to a char pointer p..(the
reason y char pointer is used u will get to know it at the end)
we know p[b] means *(p+b)....then &p[b] means &*(p+b) i.e. p+b i.e a+b
we used char pointer to increment it one by one..had we used int pointer..
it wud have incremented it +4*b.....
there is another way of doing it....
*printf("%d\n",printf("%*c%*c",a,"",b,""));
*
On Wed, Jul 13, 2011 at 1:52 PM, nicks <crazy.logic.k...@gmail.com> wrote:
> if someone has better idea...then please suggest that.....
>
> plz explain how this is calculating sum -->> sum= (int)&p[b];
>
>
> On Wed, Jul 13, 2011 at 1:50 PM, nicks <crazy.logic.k...@gmail.com> wrote:
>
>> I am looking for a code which can add without using + sign
>>
>> i searched the net and found the following code......can anyone explain me
>> whats happening in this ??
>>
>> #include<stdio.h>
>> #include<conio.h>
>> int main()
>> {
>> int a=3000,b=20,sum;
>> char *p;
>> p=(char *)a;
>> sum= (int)&p[b]; //adding a & b
>> printf("Answer is :");
>> printf("%d",sum);
>> return 0;
>> }
>>
>>
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