never mind...thanks.
On Wed, Jul 13, 2011 at 2:29 PM, dinesh bansal <bansal...@gmail.com> wrote:
> Can you explain how its working?
>
> On Wed, Jul 13, 2011 at 1:58 PM, Anika Jain <anika.jai...@gmail.com>
> wrote:
> > a better idea is use this:
> >
> > int a=9,b=4;
> > int sum=printf("%*s%*s",a,"",b,"");
> > printf("%d\n",sum);
> >
> >
> > On Wed, Jul 13, 2011 at 1:52 PM, nicks <crazy.logic.k...@gmail.com>
> wrote:
> >>
> >> if someone has better idea...then please suggest that.....
> >> plz explain how this is calculating sum -->> sum= (int)&p[b];
> >>
> >> On Wed, Jul 13, 2011 at 1:50 PM, nicks <crazy.logic.k...@gmail.com>
> wrote:
> >>>
> >>> I am looking for a code which can add without using + sign
> >>> i searched the net and found the following code......can anyone explain
> >>> me whats happening in this ??
> >>>
> >>> #include<stdio.h>
> >>> #include<conio.h>
> >>> int main()
> >>> {
> >>> int a=3000,b=20,sum;
> >>> char *p;
> >>> p=(char *)a;
> >>> sum= (int)&p[b]; //adding a & b
> >>> printf("Answer is :");
> >>> printf("%d",sum);
> >>> return 0;
> >>> }
> >>
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>
>
> --
> Dinesh Bansal
> The Law of Win says, "Let's not do it your way or my way; let's do it
> the best way."
>
--
Dinesh Bansal
The Law of Win says, "Let's not do it your way or my way; let's do it the
best way."
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