Shouldn't the value of "11000000" be -64????

On Wed, Jul 13, 2011 at 4:53 PM, Anika Jain <anika.jai...@gmail.com> wrote:

> binary equivalent of 5.2 is
> 101.0011001100110011001100110011(nonterminating)..
>
> now it is actually stored in normalised frorm in 32 bits..
> like this
> <--1 bit for sign---><-----8 bits for exponent-----><--------23 bits for
> fraction------>
> this is from higher order byte to lower order for little endian..
>
> if no. is positive sign bit is 0 else it is 1
>
> The rule says change your floating point no. in such a form that after 1st
> digit that is 1 decimal point comes sooo
> here it becomes like 1.0100110011001100110011001100110011(nonterminating) *
> 2^2
>
> so i here get an exponent of 2 as 2 here.. now in exponent 8 bits this
> exponent is stored as 127+exponent so here it becomes 10000001..
>
> now fraction here is clearly value after the decimal point i.e.
> 01001100110011001100110011001100110011(non terminationg) but only 1st 23
> bits are saved rest are left
>
> so finally wht we get is:
>
> 11000000 10100110 01100110 01100110
> (64)          (-90)         (102)        (102)
>
>
>
> On Wed, Jul 13, 2011 at 2:49 PM, Piyush Kapoor <pkjee2...@gmail.com>wrote:
>
>> why do we need a NthIntWithKBits() in this topic?
>>
>>
>> On Tue, Jul 12, 2011 at 7:58 AM, oppilas . <jatka.oppimi...@gmail.com>wrote:
>>
>>>
>>>
>>> On Mon, Jul 11, 2011 at 5:54 PM, Piyush Kapoor <pkjee2...@gmail.com>wrote:
>>>
>>>> Can anybody give a full explanation
>>>>
>>>> http://ideone.com/K1QmV
>>>
>>>>  On Sat, Jul 9, 2011 at 10:49 PM, sunny agrawal <
>>>> sunny816.i...@gmail.com> wrote:
>>>>
>>>>> try to find out the binary representation of float value 5.2
>>>>>
>>>>>
>>>>> On Sat, Jul 9, 2011 at 10:46 PM, Sangeeta <sangeeta15...@gmail.com>wrote:
>>>>>
>>>>>> int main(){
>>>>>> int i;
>>>>>> float a=5.2;
>>>>>> char *ptr;
>>>>>> ptr=(char *)&a;
>>>>>> for(i=0;i<=3;i++)
>>>>>> printf("%d ",*ptr++);
>>>>>> }
>>>>>>
>>>>>> output:
>>>>>>  102 102 -90 64.explain?
>>>>>>
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>>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> Sunny Aggrawal
>>>>> B-Tech IV year,CSI
>>>>> Indian Institute Of Technology,Roorkee
>>>>>
>>>>>
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>>>>
>>>>
>>>>
>>>> --
>>>> *Regards,*
>>>> *Piyush Kapoor,*
>>>> *CSE-IT-BHU*
>>>>
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>>>
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>>
>>
>>
>> --
>> *Regards,*
>> *Piyush Kapoor,*
>> *CSE-IT-BHU*
>>
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>
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-- 
*Regards,*
*Piyush Kapoor,*
*CSE-IT-BHU*

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