thanx i got it :)
On Mon, Jul 4, 2011 at 2:05 PM, Sandeep Jain <sandeep6...@gmail.com> wrote:
> If you try to visualize the internal representation.
> You've allocated 10 bytes.
> | h | e | l | l | o |
> | h | i |\0 |\0 |\0 |
>
> Since these are stored in linear form, so the actual representation would
> be
> | h | e | l | l | o | h | i |\0 |\0 |\0 |
>
>
> Now a[0] points to 'h' in the first row, and printf starts to print
> characters one by one till it finds null, i.e. \0
> Thus it prints from "hellohi"
> And similarly printing a[1] prints only "hi"
>
>
> Regards,
> Sandeep Jain
>
>
>
>
> On Mon, Jul 4, 2011 at 1:48 PM, Sangeeta <sangeeta15...@gmail.com> wrote:
>
>> #include<stdio.h>
>> #include<string.h>
>> void main()
>> {
>> char a[2][5]= {
>> "hellodear",
>> "hi"};
>> printf("%s%s",a[0],a[1]);
>> }
>> output:hellohi hi
>> explain?
>>
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