by using swap function is pointer to a pointer used then??
On Thu, Jul 14, 2011 at 1:36 AM, Piyush Kapoor <pkjee2...@gmail.com> wrote:
> u need a pointer to a pointer to swap the pointers...
>
>
> On Thu, Jul 14, 2011 at 1:21 AM, Anika Jain <anika.jai...@gmail.com>wrote:
>
>> can some body tell me that:
>>
>> void swap(node *p,node *q)
>> {
>> node *t;
>> t=p;
>> p=q;
>> q=t;
>> }
>>
>> void mirror(node *p)
>> {
>> if (p==NULL)
>> return;
>>
>> else
>> { mirror(p->r);
>> mirror(p->l);
>> swap(p->r,p->l);
>> }
>> }
>>
>> in this the swapping is occuring but if i do :
>>
>> void mirror(node *p)
>> {
>> if (p==NULL)
>> return;
>>
>> else
>> { mirror(p->r);
>> mirror(p->l);
>> node *t;
>> t=p->r;
>> p->r=p->l;
>> p->l=t;
>> }
>> }
>>
>>
>> here it is not getting done .. why??
>>
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>
>
>
> --
> *Regards,*
> *Piyush Kapoor,*
> *CSE-IT-BHU*
>
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