@Sagar: No problem. The algorithm would do only forward traversal
steps until it got to root_>left, whereupon F + R = K.

Dave

On Jul 16, 11:40 am, sagar pareek <sagarpar...@gmail.com> wrote:
> @dave
> what if the k= root->left + right most leaf ?
> how ur algo works on it?
>
>
>
>
>
> On Sat, Jul 16, 2011 at 9:28 PM, Dave <dave_and_da...@juno.com> wrote:
> > @Noobcoder: To do it in O(n) without destroying the BST, do two
> > inorder traversals simultaneously, one in the normal forward (left
> > subtree first) direction and one in the reverse direction (right
> > subtree first). Let the two current nodes have value F and R
> > respectively. If F + R = K, return success. If F = R, return failure.
> > If F + R < K, advance the forward traversal. Otherwise (F + R > K),
> > advance the reverse traversal. To do the traversals simultaneously,
> > you will have to use explicit stacks instead of recursion.
>
> > Dave
>
> > On Jul 16, 9:01 am, noobcoder <ase.as...@gmail.com> wrote:
> > > Given a BST containing integers, and a value K. You have to find two
> > > nodes that give sum = K.
>
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> **Regards
> SAGAR PAREEK
> COMPUTER SCIENCE AND ENGINEERING
> NIT ALLAHABAD- Hide quoted text -
>
> - Show quoted text -

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