Use O(2n) memory , list the in-order traversal of BST  say A[0..n].
and K-A[0...n]  say B . Now apply standard merge function(Merge sort)
on A and B. keeping track of equal found elements during comparison to
get the ans.

On 7/17/11, sagar pareek <sagarpar...@gmail.com> wrote:
> You must take an example and then explain
>
> On Sat, Jul 16, 2011 at 11:59 PM, Dave <dave_and_da...@juno.com> wrote:
>
>> @Sagar: If you are not getting my logic, ask a question.
>>
>> Dave
>>
>> On Jul 16, 12:35 pm, sagar pareek <sagarpar...@gmail.com> wrote:
>> > Ok may be i m not getting ur logic...
>> >
>> >
>> >
>> >
>> >
>> > On Sat, Jul 16, 2011 at 11:03 PM, Dave <dave_and_da...@juno.com> wrote:
>> > > @Sagar: No. I didn't say that they were in parallel or that one was
>> > > inside the other. Go back and read it again and you will see that I
>> > > said that they were being performed simultaneously, with each one
>> > > being advanced in certain circumstances, and that in order to do that
>> > > you would have to use explicit stacks instead of recursion. Perhaps,
>> > > instead, you misread or misunderstood it.
>> >
>> > > Dave
>> >
>> > > On Jul 16, 12:24 pm, sagar pareek <sagarpar...@gmail.com> wrote:
>> > > > ok i got it....
>> > > > actually u written wrong that f/w and reverse traversal are running
>> > > > parallel
>> > > > u must wrote that f/w traversal inside reverse or vice versa
>> >
>> > > > On Sat, Jul 16, 2011 at 10:35 PM, Dave <dave_and_da...@juno.com>
>> wrote:
>> > > > > @Sagar: No problem. The algorithm would do only forward traversal
>> > > > > steps until it got to root_>left, whereupon F + R = K.
>> >
>> > > > > Dave
>> >
>> > > > > On Jul 16, 11:40 am, sagar pareek <sagarpar...@gmail.com> wrote:
>> > > > > > @dave
>> > > > > > what if the k= root->left + right most leaf ?
>> > > > > > how ur algo works on it?
>> >
>> > > > > > On Sat, Jul 16, 2011 at 9:28 PM, Dave <dave_and_da...@juno.com>
>> > > wrote:
>> > > > > > > @Noobcoder: To do it in O(n) without destroying the BST, do
>> > > > > > > two
>> > > > > > > inorder traversals simultaneously, one in the normal forward
>> (left
>> > > > > > > subtree first) direction and one in the reverse direction
>> (right
>> > > > > > > subtree first). Let the two current nodes have value F and R
>> > > > > > > respectively. If F + R = K, return success. If F = R, return
>> > > failure.
>> > > > > > > If F + R < K, advance the forward traversal. Otherwise (F + R
>> > > > > > > >
>> K),
>> > > > > > > advance the reverse traversal. To do the traversals
>> simultaneously,
>> > > > > > > you will have to use explicit stacks instead of recursion.
>> >
>> > > > > > > Dave
>> >
>> > > > > > > On Jul 16, 9:01 am, noobcoder <ase.as...@gmail.com> wrote:
>> > > > > > > > Given a BST containing integers, and a value K. You have to
>> find
>> > > two
>> > > > > > > > nodes that give sum = K.
>> >
>> > > > > > > --
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>> > > > > > --
>> > > > > > **Regards
>> > > > > > SAGAR PAREEK
>> > > > > > COMPUTER SCIENCE AND ENGINEERING
>> > > > > > NIT ALLAHABAD- Hide quoted text -
>> >
>> > > > > > - Show quoted text -
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>> > > > COMPUTER SCIENCE AND ENGINEERING
>> > > > NIT ALLAHABAD- Hide quoted text -
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>> > COMPUTER SCIENCE AND ENGINEERING
>> > NIT ALLAHABAD- Hide quoted text -
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> SAGAR PAREEK
> COMPUTER SCIENCE AND ENGINEERING
> NIT ALLAHABAD
>
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