@Popli : Bingo , that is what i was thinking and mentioned in my previous
post......

On Wed, Jul 20, 2011 at 7:08 PM, Gaurav Popli <abeygau...@gmail.com> wrote:

> i want to ask one thing...the way some are saying first check with 2
> then 4 and then 16....to reach at that place we are suppose to
> traverse it and also hav eto put a condition say like count<n or
> something...in this case also we are comparing so whats the
> use....correct me if im wrong.....
>
> On Wed, Jul 20, 2011 at 6:58 PM, bittu <shashank7andr...@gmail.com> wrote:
> > can be done in O(n) find tow nodes from starting position find two
> > nodes p,q such that p < k & k < q as linked list is sorted we have to
> > keep going on in right direction complexity will no less then O(N) as
> > its linked list there is no notion of binary search sorted linked list
> > think out why ?
> >
> > only think we can apply some logic to reduce the comparisons that's i
> > also think will be gr8 improvement but approach sounds good if start
> > comparing the nodes value using multiple of 2 fact .e.g. take an
> > integer i=2^j & from j=0 to start comparing 2^0th node, 2^1th node,
> > 2^2th node....2^jth node might be we are able to reduce the number of
> > comparisons
> >
> > do notify me via gmail if i am wrong if u find difficulty in TC ? else
> > happy learning
> >
> > if this would have been sorted array then we could have been solved it
> > O(logn) suing same approach.
> >
> >
> > Thanks
> > Shashank Mani
> > Computer Science
> > Birla Institute of Technology, Mesra
> >
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-- 
Ankur Khurana
Computer Science , 4th year
Netaji Subhas Institute Of Technology
Delhi.

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