@anika: Now I am able to understand.thanks anyways.:)
On Thu, Jul 21, 2011 at 1:18 AM, Kamakshii Aggarwal
<kamakshi...@gmail.com>wrote:
> anika can u pls explain ur solution.I am not getting it.
>
>
> On Wed, Jul 20, 2011 at 1:27 PM, Anurag atri <anu.anurag....@gmail.com>wrote:
>
>> int a = 20 ; //whatever value you like
>> int b = 30 ; // again
>>
>> int sum = a - (-b) ;
>> cout <<sum ;
>>
>> //eh ?
>>
>>
>> On Wed, Jul 13, 2011 at 6:17 PM, vaibhav shukla
>> <vaibhav200...@gmail.com>wrote:
>>
>>> :D :D .... ;)
>>>
>>>
>>> On Wed, Jul 13, 2011 at 6:11 PM, Anika Jain <anika.jai...@gmail.com>wrote:
>>>
>>>> @ vaibhav: ohh sorry, ya its leaving the columns..
>>>> so we can do
>>>>
>>>>
>>>> int a=9,b=4;
>>>> int sum=printf("%*s%*s",a,"",b,"");
>>>> printf("\r%d\n",sum);
>>>>
>>>>
>>>> On Wed, Jul 13, 2011 at 6:09 PM, Anika Jain <anika.jai...@gmail.com>wrote:
>>>>
>>>>> @vaibhav: no it wont coz its printing empty strings.. nothing will be
>>>>> printed
>>>>>
>>>>>
>>>>> On Wed, Jul 13, 2011 at 4:42 PM, vaibhav shukla <
>>>>> vaibhav200...@gmail.com> wrote:
>>>>>
>>>>>> @anika : ur ans will give the sum but will also leave that much amount
>>>>>> of space before printing the sum
>>>>>>
>>>>>>
>>>>>> one betther idea is to use bitwise
>>>>>>
>>>>>>
>>>>>> int Mysum(int a,int b)
>>>>>> {
>>>>>> if(b==0)
>>>>>> return a;
>>>>>> else
>>>>>> {
>>>>>> int sum=a^b;
>>>>>> int carry=(a&b)<<1;
>>>>>> return Mysum(sum,carry);
>>>>>>
>>>>>> }
>>>>>>
>>>>>>
>>>>>> On Wed, Jul 13, 2011 at 4:15 PM, dinesh bansal
>>>>>> <bansal...@gmail.com>wrote:
>>>>>>
>>>>>>> never mind...thanks.
>>>>>>>
>>>>>>>
>>>>>>> On Wed, Jul 13, 2011 at 2:29 PM, dinesh bansal
>>>>>>> <bansal...@gmail.com>wrote:
>>>>>>>
>>>>>>>> Can you explain how its working?
>>>>>>>>
>>>>>>>> On Wed, Jul 13, 2011 at 1:58 PM, Anika Jain <anika.jai...@gmail.com>
>>>>>>>> wrote:
>>>>>>>> > a better idea is use this:
>>>>>>>> >
>>>>>>>> > int a=9,b=4;
>>>>>>>> > int sum=printf("%*s%*s",a,"",b,"");
>>>>>>>> > printf("%d\n",sum);
>>>>>>>> >
>>>>>>>> >
>>>>>>>> > On Wed, Jul 13, 2011 at 1:52 PM, nicks <
>>>>>>>> crazy.logic.k...@gmail.com> wrote:
>>>>>>>> >>
>>>>>>>> >> if someone has better idea...then please suggest that.....
>>>>>>>> >> plz explain how this is calculating sum -->> sum= (int)&p[b];
>>>>>>>> >>
>>>>>>>> >> On Wed, Jul 13, 2011 at 1:50 PM, nicks <
>>>>>>>> crazy.logic.k...@gmail.com> wrote:
>>>>>>>> >>>
>>>>>>>> >>> I am looking for a code which can add without using + sign
>>>>>>>> >>> i searched the net and found the following code......can anyone
>>>>>>>> explain
>>>>>>>> >>> me whats happening in this ??
>>>>>>>> >>>
>>>>>>>> >>> #include<stdio.h>
>>>>>>>> >>> #include<conio.h>
>>>>>>>> >>> int main()
>>>>>>>> >>> {
>>>>>>>> >>> int a=3000,b=20,sum;
>>>>>>>> >>> char *p;
>>>>>>>> >>> p=(char *)a;
>>>>>>>> >>> sum= (int)&p[b]; //adding a & b
>>>>>>>> >>> printf("Answer is :");
>>>>>>>> >>> printf("%d",sum);
>>>>>>>> >>> return 0;
>>>>>>>> >>> }
>>>>>>>> >>
>>>>>>>> >> --
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>>>>>>>> >
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>>>>>>>>
>>>>>>>>
>>>>>>>>
>>>>>>>> --
>>>>>>>> Dinesh Bansal
>>>>>>>> The Law of Win says, "Let's not do it your way or my way; let's do
>>>>>>>> it
>>>>>>>> the best way."
>>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> --
>>>>>>> Dinesh Bansal
>>>>>>> The Law of Win says, "Let's not do it your way or my way; let's do it
>>>>>>> the best way."
>>>>>>>
>>>>>>> --
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>>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>> --
>>>>>> best wishes!!
>>>>>> Vaibhav Shukla
>>>>>> DU-MCA
>>>>>>
>>>>>> --
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>>>>>>
>>>>>
>>>>>
>>>> --
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>>>>
>>>
>>>
>>>
>>> --
>>> best wishes!!
>>> Vaibhav Shukla
>>> DU-MCA
>>>
>>> --
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>>
>>
>>
>> --
>> Regards
>> Anurag Atri
>> III year
>> Computer Engineering
>> Delhi College Of Engineering
>>
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>
>
>
> --
> Regards,
> Kamakshi
> kamakshi...@gmail.com
>
--
Regards,
Kamakshi
kamakshi...@gmail.com
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