But the argument to the function is passed as a pointer to an object not by
value then why its not working..

On Thu, Jul 21, 2011 at 5:45 PM, dinesh bansal <bansa...@gmail.com> wrote:

> Value which is changed inside a function will not be reflected after call.
> So you are setting b as pointer to class a but this value will not retain
> after function call in main().
>
>
>
> On Thu, Jul 21, 2011 at 5:40 PM, Saurabh <saurabh24...@gmail.com> wrote:
>
>> Can any one explain why the following program not giving the correct
>> output.
>>
>> #include <iostream>
>> using namespace std;
>> class a
>> {
>>        int x;
>>
>>        public:
>>                void set(int y)
>>                {
>>                                x=y;
>>                }
>>                int get()
>>                {
>>                       return x;
>>                }
>>
>> };
>> void f(a * b)
>> {
>>      b = new a();
>>      b->set(5);
>> }
>> int main()
>> {
>>      a *a1;
>>      f(a1);
>>      cout<<"x = "<<a1->get();
>>     return 0;
>> }
>>
>>
>>
>> --
>> Regards
>> Saurabh
>>
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>
>
>
> --
> Dinesh Bansal
> The Law of Win says, "Let's not do it your way or my way; let's do it the
> best way."
>
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-- 
Regards  n Luv
Saurabh Badhai

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