You can also do
void f(a ** b)
{
(*b) = new a();
(*b)->set(5);
}
int main()
{
a *a1;
f(&a1);
cout<<"x = "<<a1->get();
return 0;
}
The logic behind this is the basic difference between call by value and call
by reference :-) In your original code, the changes in b will not reflect in
a. In C you achieve it by using double pointers, and in C++ you can achieve
it by using the & operator! :-)
--
Kashyap.K,
III year, B.E. CSE,
College of Engineering Guindy,
Anna University,
Chennai.
--
If you've never failed, you've never lived!
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