sorry for above...typo mistake :-

yup
but what about this
x=3;
y= x++ + ++x + ++x; // it is executed as:-

during first addition, increase the value of x, now first addition will be
4+4 + ++x;
now for second addition it will be like
8+5
hence final value of y=13;
do it by urself

On Sat, Jul 23, 2011 at 6:09 PM, sagar pareek <sagarpar...@gmail.com> wrote:

> yup
> but what about this
> x=4;
> y= x++ + ++x + ++x; // it is executed as:-
>
> during first addition, increase the value of x, now first addition will be
> 4+4 + ++x;
> now for second addition it will be like
> 8+5
> hence final value of y=13;
> do it by urself
>
> On Sat, Jul 23, 2011 at 2:54 PM, shady <sinv...@gmail.com> wrote:
>
>> @sagar
>> would it get evaluated like this ?
>> supposing x = 3;
>>
>> y = x++ + ++x; becomes y = (x=x+1) + (x=x+1);
>> then x=x+1;
>>
>> so x = 5, y = 8;
>>
>> On Sat, Jul 23, 2011 at 2:48 PM, sagar pareek <sagarpar...@gmail.com>wrote:
>>
>>> @Venga
>>> if u are doing this
>>> y= x++ + ++x; //x=3
>>> then it would be
>>> like that :-
>>> ++x; //x=4
>>> y=x+x;
>>> x++;
>>>
>>> i thing this is sufficient  :)
>>>
>>> On Sat, Jul 23, 2011 at 1:20 PM, Interstellar Overdrive <
>>> abhi123khat...@gmail.com> wrote:
>>>
>>>> The expression y = x++ + x++ + ++y;  is not a valid one. The result is
>>>> compiler dependent
>>>> Read this for reference :http://c-faq.com/expr/seqpoints.html
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
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>>>
>>>
>>> --
>>> **Regards
>>> SAGAR PAREEK
>>> COMPUTER SCIENCE AND ENGINEERING
>>> NIT ALLAHABAD
>>>
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>
>
>
> --
> **Regards
> SAGAR PAREEK
> COMPUTER SCIENCE AND ENGINEERING
> NIT ALLAHABAD
>
>


-- 
**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD

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