thanks sagar!
so just to confirm ,what i get from above is that the x value before the
first addition is first updated from 3 to 5( due to 2 pre increments) and
then 5 and  5 is added to make the 10.This is then added to 6( as before the
second addition x is updated again)

if y = x++ + ++x + x++
then will the value seem like for the first addition(x++ + ++x ) as
4+4?(since the single pre increment increases the value of x by 1) ,and then
for the next addition it would be 8+4(since post increment here so x doesnt
change)?finally the value of x is 6?
pls correct me if wrong ...




On Mon, Jul 25, 2011 at 10:21 AM, sagar pareek <sagarpar...@gmail.com>wrote:

> Well its not like that
> first u have x=3;
> now u have to do
> y=++x + ++x + ++X;
> before doing first addition
> y=(++x + ++x) + ++x;
>        ^          ^
>
> above spotted x will increase , before their addition
> and then
> y= 5+5 + ++x;
> now
> y=10+ 6
> y=16;
>
> hope u now get it :)
>
>
> On Sun, Jul 24, 2011 at 2:30 PM, Arun Vishwanathan <aaron.nar...@gmail.com
> > wrote:
>
>> *x= 3 initially
>>
>>
>> On Sun, Jul 24, 2011 at 11:00 AM, Arun Vishwanathan <
>> aaron.nar...@gmail.com> wrote:
>>
>>> if that is the case as u say, then wont it be 3+ 4+ 5 when x +3
>>> initially?..and then x increments by one later due to the single post
>>> increment
>>>
>>>
>>> On Sun, Jul 24, 2011 at 10:15 AM, sagar pareek <sagarpar...@gmail.com>wrote:
>>>
>>>> nope compiler read it from left to right
>>>>
>>>>
>>>> On Sun, Jul 24, 2011 at 12:05 AM, Arun Vishwanathan <
>>>> aaron.nar...@gmail.com> wrote:
>>>>
>>>>> @sagar: if what u said previously holds as in when u say y=x++ + ++x is
>>>>> evaluated as 4+4 since ++x results in 4 and 4 is used in x++ too (cos post
>>>>> increment increments x later) then for y=x++ + ++x + ++x with x beginning 
>>>>> as
>>>>> 3 shud the expression not be evaluated as 5+5+4( from rhs ++x does a 3 to 
>>>>> 4
>>>>> and another ++x does 4 to 5 and 5 is used in x++) .later x becomes 6 ?
>>>>>
>>>>>
>>>>>
>>>>>
>>>>> On Sat, Jul 23, 2011 at 2:39 PM, sagar pareek 
>>>>> <sagarpar...@gmail.com>wrote:
>>>>>
>>>>>> sorry for above...typo mistake :-
>>>>>>
>>>>>>  yup
>>>>>> but what about this
>>>>>> x=3;
>>>>>>  y= x++ + ++x + ++x; // it is executed as:-
>>>>>>
>>>>>> during first addition, increase the value of x, now first addition
>>>>>> will be 4+4 + ++x;
>>>>>> now for second addition it will be like
>>>>>> 8+5
>>>>>> hence final value of y=13;
>>>>>> do it by urself
>>>>>>
>>>>>> On Sat, Jul 23, 2011 at 6:09 PM, sagar pareek 
>>>>>> <sagarpar...@gmail.com>wrote:
>>>>>>
>>>>>>> yup
>>>>>>> but what about this
>>>>>>> x=4;
>>>>>>> y= x++ + ++x + ++x; // it is executed as:-
>>>>>>>
>>>>>>> during first addition, increase the value of x, now first addition
>>>>>>> will be 4+4 + ++x;
>>>>>>> now for second addition it will be like
>>>>>>> 8+5
>>>>>>> hence final value of y=13;
>>>>>>> do it by urself
>>>>>>>
>>>>>>> On Sat, Jul 23, 2011 at 2:54 PM, shady <sinv...@gmail.com> wrote:
>>>>>>>
>>>>>>>> @sagar
>>>>>>>> would it get evaluated like this ?
>>>>>>>> supposing x = 3;
>>>>>>>>
>>>>>>>> y = x++ + ++x; becomes y = (x=x+1) + (x=x+1);
>>>>>>>> then x=x+1;
>>>>>>>>
>>>>>>>> so x = 5, y = 8;
>>>>>>>>
>>>>>>>> On Sat, Jul 23, 2011 at 2:48 PM, sagar pareek <
>>>>>>>> sagarpar...@gmail.com> wrote:
>>>>>>>>
>>>>>>>>> @Venga
>>>>>>>>> if u are doing this
>>>>>>>>> y= x++ + ++x; //x=3
>>>>>>>>> then it would be
>>>>>>>>> like that :-
>>>>>>>>> ++x; //x=4
>>>>>>>>> y=x+x;
>>>>>>>>> x++;
>>>>>>>>>
>>>>>>>>> i thing this is sufficient  :)
>>>>>>>>>
>>>>>>>>> On Sat, Jul 23, 2011 at 1:20 PM, Interstellar Overdrive <
>>>>>>>>> abhi123khat...@gmail.com> wrote:
>>>>>>>>>
>>>>>>>>>> The expression y = x++ + x++ + ++y;  is not a valid one. The
>>>>>>>>>> result is compiler dependent
>>>>>>>>>> Read this for reference :http://c-faq.com/expr/seqpoints.html
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> --
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>>>>>>>>>
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> --
>>>>>>>>> **Regards
>>>>>>>>> SAGAR PAREEK
>>>>>>>>> COMPUTER SCIENCE AND ENGINEERING
>>>>>>>>> NIT ALLAHABAD
>>>>>>>>>
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>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> --
>>>>>>> **Regards
>>>>>>> SAGAR PAREEK
>>>>>>> COMPUTER SCIENCE AND ENGINEERING
>>>>>>> NIT ALLAHABAD
>>>>>>>
>>>>>>>
>>>>>>
>>>>>>
>>>>>> --
>>>>>> **Regards
>>>>>> SAGAR PAREEK
>>>>>> COMPUTER SCIENCE AND ENGINEERING
>>>>>> NIT ALLAHABAD
>>>>>>
>>>>>>   --
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>>>>>
>>>>>
>>>>>
>>>>> --
>>>>>  Arun Vish
>>>>> Graduate Student
>>>>> Department of Computer Science
>>>>> University of Southern California
>>>>>
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>>>>
>>>>
>>>> --
>>>> **Regards
>>>> SAGAR PAREEK
>>>> COMPUTER SCIENCE AND ENGINEERING
>>>> NIT ALLAHABAD
>>>>
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>>>
>>>
>>>
>>> --
>>>  Arun Vish
>>> Graduate Student
>>> Department of Computer Science
>>> University of Southern California
>>>
>>>
>>
>>
>> --
>>  Arun Vish
>> Graduate Student
>> Department of Computer Science
>> University of Southern California
>>
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>
>
>
> --
> **Regards
> SAGAR PAREEK
> COMPUTER SCIENCE AND ENGINEERING
> NIT ALLAHABAD
>
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