there's a lot diff b/w &a and &a+1.
try to figure out what type of pointer ptr is ?
yes its int* type
so during assignment &a will assign address of a
and &a+1 will give u address of sizeof(arr) * sizeof(int);
but actually ptr is still int* type..
i hope u get it...
On Mon, Jul 25, 2011 at 8:20 PM, swetha rahul <swetharahu...@gmail.com>wrote:
> int main()
> {
> int a[5]={1,2,3,4,5};
> int *ptr=&a;
> printf("%d",*(ptr));
> getch();
> }
>
> Then why this prints 1.. ??
>
>
> On Mon, Jul 25, 2011 at 7:50 PM, sagar pareek <sagarpar...@gmail.com>wrote:
>
>> here &a is data type with 5*sizeof(int)
>> so &a+1 will give u next address just after the alloted whole array
>>
>>
>> On Mon, Jul 25, 2011 at 7:44 PM, swetha rahul <swetharahu...@gmail.com>wrote:
>>
>>> Hi,
>>>
>>> int main()
>>> {
>>> int a[5]={1,2,3,4,5};
>>> int *ptr=&a+1;
>>> printf("%d",*(ptr-1));
>>> }
>>>
>>> It prints 5... Can somebody explain wats happening here..?
>>>
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>>
>>
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>> SAGAR PAREEK
>> COMPUTER SCIENCE AND ENGINEERING
>> NIT ALLAHABAD
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