its because of side effect where value of i is getting changed twice in a
single line.
correct me if i am wrong :)
*Muthuraj R.
4TH Year BE.**
Information Science Dept*
*PESIT, Bengaluru .
*
On Mon, Jul 25, 2011 at 11:01 PM, geek forgeek <geekhori...@gmail.com>wrote:
> y not the output is 3 2 coz on right to left evaluation of printf i shud
> be left shifted by 1 bit wgich shud make it 2 ??
>
>
> On Mon, Jul 25, 2011 at 10:28 AM, sameer.mut...@gmail.com <
> sameer.mut...@gmail.com> wrote:
>
>> yeah output
>> 0
>> 1 1
>> *is dis because of side effect? *
>> * *
>> *
>> *
>> *Muthuraj R.
>> 4TH Year BE.**
>> Information Science Dept*
>> *PESIT, Bengaluru .
>> *
>>
>>
>>
>>
>>
>> On Mon, Jul 25, 2011 at 10:49 PM, Deoki Nandan <deok...@gmail.com> wrote:
>>
>>> run on gcc compiler it would be
>>> 0
>>> 1 1
>>>
>>>
>>> On Mon, Jul 25, 2011 at 10:35 PM, geek forgeek <geekhori...@gmail.com>wrote:
>>>
>>>> 1.
>>>> #include<stdio.h>
>>>> main()
>>>> {
>>>> int i=1;
>>>> printf("\n%d",i^=1%2);
>>>> printf("\n%d %d",i^=1%2,i<<=1%2);
>>>> return 0;
>>>> }
>>>>
>>>> output 3 3
>>>> hey shudnt the output be 3 2
>>>>
>>>>
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>>>
>>>
>>>
>>> --
>>> **With Regards
>>> Deoki Nandan Vishwakarma
>>>
>>> *
>>> *
>>>
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