@sameer I think that is right
On Mon, Jul 25, 2011 at 11:02 PM, sameer.mut...@gmail.com <
sameer.mut...@gmail.com> wrote:
> its because of side effect where value of i is getting changed twice in a
> single line.
> correct me if i am wrong :)
>
> *Muthuraj R.
> 4TH Year BE.**
> Information Science Dept*
> *PESIT, Bengaluru .
> *
>
>
>
>
> On Mon, Jul 25, 2011 at 11:01 PM, geek forgeek <geekhori...@gmail.com>wrote:
>
>> y not the output is 3 2 coz on right to left evaluation of printf i shud
>> be left shifted by 1 bit wgich shud make it 2 ??
>>
>>
>> On Mon, Jul 25, 2011 at 10:28 AM, sameer.mut...@gmail.com <
>> sameer.mut...@gmail.com> wrote:
>>
>>> yeah output
>>> 0
>>> 1 1
>>> *is dis because of side effect? *
>>> * *
>>> *
>>> *
>>> *Muthuraj R.
>>> 4TH Year BE.**
>>> Information Science Dept*
>>> *PESIT, Bengaluru .
>>> *
>>>
>>>
>>>
>>>
>>>
>>> On Mon, Jul 25, 2011 at 10:49 PM, Deoki Nandan <deok...@gmail.com>wrote:
>>>
>>>> run on gcc compiler it would be
>>>> 0
>>>> 1 1
>>>>
>>>>
>>>> On Mon, Jul 25, 2011 at 10:35 PM, geek forgeek
>>>> <geekhori...@gmail.com>wrote:
>>>>
>>>>> 1.
>>>>> #include<stdio.h>
>>>>> main()
>>>>> {
>>>>> int i=1;
>>>>> printf("\n%d",i^=1%2);
>>>>> printf("\n%d %d",i^=1%2,i<<=1%2);
>>>>> return 0;
>>>>> }
>>>>>
>>>>> output 3 3
>>>>> hey shudnt the output be 3 2
>>>>>
>>>>>
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>>>>
>>>>
>>>>
>>>> --
>>>> **With Regards
>>>> Deoki Nandan Vishwakarma
>>>>
>>>> *
>>>> *
>>>>
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Regards
Rajeev N B <http://www.opensourcemania.co.cc>
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