@akshata: here padding wont come into picture coz int a =4byte, char
*b[5]=4*5byte, *link=4byte all are multiple of 4 . ans will be 28 byte
On Tue, Jul 26, 2011 at 6:42 PM, Akshata Sharma
<akshatasharm...@gmail.com>wrote:
> why isn't padding done here? We have seen previous posts on size of
> structures, where due to padding, the size was not just the sum of size of
> datatypes, but also padded bytes.
> like here, int (4 bytes), then why is 3 bytes not padded after this, before
> char* arr[5] (20 bytes)?
>
>
> On Tue, Jul 26, 2011 at 6:16 PM, sunny agrawal <sunny816.i...@gmail.com>wrote:
>
>> 4+20+4 = 28 bytes it should be i think
>>
>> On Tue, Jul 26, 2011 at 6:10 PM, Puneet Gautam
>> <puneet.nsi...@gmail.com>wrote:
>>
>>> #include<stdio.h>
>>> #include<stddef.h>
>>> struct node{
>>> int a;
>>> char *b[5];
>>> struct node *link;
>>> };
>>> main()
>>> {
>>> int a;
>>> a=sizeof(struct node);
>>> printf("%d",a);
>>> getchar();
>>> return 0;
>>> }
>>>
>>> Whats the output..?
>>>
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>>
>>
>> --
>> Sunny Aggrawal
>> B-Tech IV year,CSI
>> Indian Institute Of Technology,Roorkee
>>
>>
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