C i guess ur comfortable wid the frst 3...
now in fourth c the order of evaluation frst x<y is evaluated as < has
higher precedence that +=...since both r 3...so condition is false and y++
is taken...so z+=y++ takes place...
z ws 1 and y=3...so z becomes 4 and it is printed... and after this y
becomes 4... and since x++ ws not evaluated it retains its value of 3...
in the next one z>=y takes place frst( associativity of >= is left to right)
,since it is true it become 1 now 1>=x is false hence ans 0...
in the last both z>=y and y>=x are true hence 1
i hope it is clear...
hence the ans 3 4 4 fr the next printf
On Wed, Jul 27, 2011 at 9:33 PM, Vijay Khandar <vijaykhand...@gmail.com>wrote:
> #include<stdio.h>
> #include<conio.h>
> void main()
> {
> clrscr();
> int x=1,y=1,z=1;
> x+=y+=z;
> printf("\n %d\n ",x<y?y:x);
> printf("\n %d\n",x<y?x++:y++);
> printf("\n %d %d\n",x,y);
> printf("\n %d\n",z+=x<y?x++:y++);
> printf("\n %d %d %d\n",x,y,z);
> x=3;y=z=4;
> printf("\n %d\n",z>=y>=x?1:0);
> printf("\n %d\n",z>=y&&y>=x);
> getch();
> }
>
> I m getting o/p as--
> 3
> 2
> 3 3
> 4
> 3 4 4
> 0
> 1
>
> I m confusing fm fourth printf...plz explain me..........
>
> Vijay.............
>
> --
> You received this message because you are subscribed to the Google Groups
> "Algorithm Geeks" group.
> To post to this group, send email to algogeeks@googlegroups.com.
> To unsubscribe from this group, send email to
> algogeeks+unsubscr...@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/algogeeks?hl=en.
>
>
--
Aditi Garg
Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi
9718388816
--
You received this message because you are subscribed to the Google Groups
"Algorithm Geeks" group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.
