when you use itoa , what you get is a string. get the sum of all the digits , using c-'0' and then use repeated subtraction . . .
On Sat, Jul 30, 2011 at 1:01 AM, sukhmeet singh <sukhmeet2...@gmail.com>wrote: > repeated subtraction !! > > On Sat, Jul 30, 2011 at 12:52 AM, nivedita arora < > vivaciousnived...@gmail.com> wrote: > >> Without using /,% and * operators. write a function to divide a number >> by 3. itoa() function is available. >> >> all i cn thnk of is to use shift operator and addition , x/3=e^(logx- >> log3) or repetitive subtraction >> >> but none of them uses itoa() ..ne idea how its done? >> thnks ! >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> >> > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Ankur Khurana Computer Science Netaji Subhas Institute Of Technology Delhi. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
